Candidates preparing for JEE Advanced 2026 can download the official syllabus PDF from jeeadv.ac.in, released by IIT Roorkee.

To be eligible for JEE Advanced 2026, candidates must rank among the top 2.5 lakh students in JEE Main 2026, satisfy the age ...

To be eligible for JEE Advanced 2026, candidates must rank among the top 2.5 lakh students in JEE Main 2026, satisfy the age criteria. Additionally, candidates must have appeared for their Class 12 ...

The JEE Advanced 2026 syllabus PDF is now available on the official website, jeeadv.ac.in. The detailed syllabus provides ...

Solution: det (A) = −5, and for n×n matrix adj (A) has determinant (det A)^ (n−1). Here n = 3, so det (B) = (−5)^ (2) = 25.

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