This means that, using Pythagoras’ theorem, the equation of a circle with radius \(r\) and centre (0, 0) is given by the formula \(x^2+ y^2= r^2\). Find the equation of a circle with radius 3 ...
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380-year-old Descartes circle problem finally solved with help from physicsUsing advanced mathematical tools inspired by physics, the team has derived a general equation for any number of tangent ...
A tangent to a circle at point P is a straight ... {2}\), in to the formula \(y = mx + c\) gives: So the equation of the tangent \(y = -\frac{1}{2} x + 5\) Finally, the point where the tangent ...
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