Solution: det (A) = −5, and for n×n matrix adj (A) has determinant (det A)^ (n−1). Here n = 3, so det (B) = (−5)^ (2) = 25.
Gear-obsessed editors choose every product we review. We may earn commission if you buy from a link. Why Trust Us? Representation theory transforms abstract algebra groups into things like simpler ...
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